Select the true statement about triangle ABC.
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
2. Recall trigonometric ratios in a right-angled triangle: For an acute angle in a right-angled triangle:
- Sine (sin) = Opposite / Hypotenuse
- Cosine (cos) = Adjacent / Hypotenuse
- Tangent (tan) = Opposite / Adjacent
3. Calculate the trigonometric values for angle A:
- The side opposite to angle A is BC, which has a length of 5.
- The side adjacent to angle A is AB, which has a length of 12.
- The hypotenuse is AC, which has a length of 13.
Therefore:
- $\cos A = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{AB}{AC} = \frac{12}{13}$
- $\sin A = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{BC}{AC} = \frac{5}{13}$
- $\tan A = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{BC}{AB} = \frac{5}{12}$
4. Calculate the trigonometric values for angle C:
- The side opposite to angle C is AB, which has a length of 12.
- The side adjacent to angle C is BC, which has a length of 5.
- The hypotenuse is AC, which has a length of 13.
Therefore:
- $\cos C = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{BC}{AC} = \frac{5}{13}$
- $\sin C = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{AB}{AC} = \frac{12}{13}$
- $\tan C = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{AB}{BC} = \frac{12}{5}$
5. Evaluate the given statements:
- A. $\cos A = \sin C$: We calculated $\cos A = \frac{12}{13}$ and $\sin C = \frac{12}{13}$. So, $\frac{12}{13} = \frac{12}{13}$. This statement is true.
- B. $\cos A = \cos C$: We calculated $\cos A = \frac{12}{13}$ and $\cos C = \frac{5}{13}$. So, $\frac{12}{13} \neq \frac{5}{13}$. This statement is false.
- C. $\cos A = \sin B$: Angle B is the right angle ($90^\circ$). The trigonometric functions for $90^\circ$ are $\sin 90^\circ = 1$ and $\cos 90^\circ = 0$. $\cos A = \frac{12}{13}$, which is not equal to 1. This statement is false.
- D. $\cos A = \tan C$: We calculated $\cos A = \frac{12}{13}$ and $\tan C = \frac{12}{5}$. So, $\frac{12}{13} \neq \frac{12}{5}$. This statement is false.