Contestants on a gameshow spin a wheel with 24 equally-sized segments. Most of thos...
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
4. Calculate the probability of NOT landing on "bankrupt" in two consecutive spins: Since the outcome of one spin does not affect the outcome of future spins, the two spins are independent events. The probability of two independent events both occurring is the product of their individual probabilities. Therefore, the probability that NEITHER of the two spins land on "bankrupt" is: $P(\text{not bankrupt on 1st spin AND not bankrupt on 2nd spin}) = P(\text{not bankrupt on 1st spin}) \times P(\text{not bankrupt on 2nd spin})$.
$$P(\text{neither bankrupt}) = \frac{11}{12} \times \frac{11}{12} = \frac{121}{144}$$