A ball is thrown into the air. Its height h, in feet, after x seconds is given by t...
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
The function is in vertex form $h(x) = a(x-h)^2 + k$, where the vertex is $(h, k)$. For $h(x) = -16(x - 1)^2 + 23$, the vertex is $(1, 23)$. This means at $x=1$ second, the height $h=23$ feet, which is the maximum height.