In triangle ABC, m<A = 25 degrees, m<C = 61 degrees, and b = 38. Solve for the othe...
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
1. Find the measure of angle B: The sum of angles in a triangle is $180^\circ$. Given $m\angle A = 25^\circ$ and $m\angle C = 61^\circ$, we can find $m\angle B$ by subtracting the sum of the known angles from $180^\circ$.
$m\angle B = 180^\circ - m\angle A - m\angle C$
$m\angle B = 180^\circ - 25^\circ - 61^\circ$
$m\angle B = 180^\circ - 86^\circ$
$m\angle B = 94^\circ$
2. Use the Law of Sines to find side c: The Law of Sines states that for any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. We have angle A and side a (opposite A), angle B and side b (opposite B), and angle C and side c (opposite C). We are given side b and want to find side c. We know angles A, B, and C.
$$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$$
We will use the portion $\frac{b}{\sin B} = \frac{c}{\sin C}$ to solve for c.
We are given $b = 38$, $m\angle B = 94^\circ$, and $m\angle C = 61^\circ$.
$$\frac{38}{\sin 94^\circ} = \frac{c}{\sin 61^\circ}$$
Now, solve for c:
$$c = \frac{38 \cdot \sin 61^\circ}{\sin 94^\circ}$$
Using a calculator:
$$c \approx \frac{38 \cdot 0.8746}{0.9976}$$
$$c \approx \frac{33.2348}{0.9976}$$
$$c \approx 33.31$$
So, option A, $c = 33.3$, is approximately correct.
3. Use the Law of Sines to find side a: We will use the portion $\frac{a}{\sin A} = \frac{b}{\sin B}$ to solve for a.
We are given $b = 38$, $m\angle B = 94^\circ$, and $m\angle A = 25^\circ$.
$$\frac{a}{\sin 25^\circ} = \frac{38}{\sin 94^\circ}$$
Now, solve for a:
$$a = \frac{38 \cdot \sin 25^\circ}{\sin 94^\circ}$$
Using a calculator:
$$a \approx \frac{38 \cdot 0.4226}{0.9976}$$
$$a \approx \frac{16.0588}{0.9976}$$
$$a \approx 16.09$$
So, option B, $a = 18.4$, is not correct.