What is the quotient of (x^3 + 6x^2 + 11x + 6) divided by (x^2 + 4x + 3)?
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
```
____________
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
```
```
x _________
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
```
```
x _________
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
-(x^3 + 4x^2 + 3x)
```
4. Subtract the result from the dividend: Subtract the product from the dividend. Remember to change the signs of the terms being subtracted:
$(x^3 + 6x^2 + 11x + 6) - (x^3 + 4x^2 + 3x) = x^3 - x^3 + 6x^2 - 4x^2 + 11x - 3x + 6 = 2x^2 + 8x + 6$.
```
x _________
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
-(x^3 + 4x^2 + 3x)
----------------
2x^2 + 8x + 6
```
```
x + 2
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
-(x^3 + 4x^2 + 3x)
----------------
2x^2 + 8x + 6
```
```
x + 2
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
-(x^3 + 4x^2 + 3x)
----------------
2x^2 + 8x + 6
-(2x^2 + 8x + 6)
```
8. Subtract again: Subtract the product from the current dividend:
$(2x^2 + 8x + 6) - (2x^2 + 8x + 6) = 0$.
```
x + 2
x^2+4x+3 | x^3 + 6x^2 + 11x + 6
-(x^3 + 4x^2 + 3x)
----------------
2x^2 + 8x + 6
-(2x^2 + 8x + 6)
----------------
0
```