A local charity is selling calendars for 10 each and packs of gum for 1.50. The cha...
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Problem
A local charity is selling calendars for $10 each and packs of gum for $1.50. The charity wants to raise more than $200. The inequality 10x + 1.50y > 200 represents the situation. Graph the solution to the inequality.
Step-by-step solution
The inequality is $10x + 1.50y > 200$. To graph this, we find the intercepts. If $x=0$, $1.50y = 200$, so $y = 200/1.50 \approx 133.33$. If $y=0$, $10x = 200$, so $x = 20$. The line passes through $(20,0)$ and $(0, 133.33)$. Since it's '>', the line is dashed and the region above the line is shaded. Graph C matches these conditions.
Answer
C