Work out the equation of the straight line shown below. Give your answer in the for...

1. Identify two points on the line: By observing the graph, we can identify two distinct points that lie on the straight line. Let's choose the points where the line intersects the y-axis and another clear point. The line intersects the y-axis at $(0, 6)$. Another point on the line appears to be $(2, 0)$.

2. Calculate the slope (m): The slope of a straight line is calculated using the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are two points on the line.
Using the points $(0, 6)$ and $(2, 0)$:
$m = \frac{0 - 6}{2 - 0} = \frac{-6}{2} = -3$.
So, the slope $m = -3$.

1. Determine the y-intercept (c): The y-intercept is the point where the line crosses the y-axis. From the graph, we can see that the line crosses the y-axis at $y = 6$. Therefore, the y-intercept $c = 6$.

4. Write the equation of the line: The equation of a straight line is given in the form $y = mx + c$. Substitute the calculated values of $m$ and $c$ into this equation.
$y = (-3)x + 6$
$y = -3x + 6$