rhombus angle property problem

In a rhombus, diagonals bisect the angles. Since $ABCD$ is a rhombus, $\triangle ABD$ is isosceles with $AB=AD$, so $\angle ABD = \angle ADB$. However, the diagram shows $\angle CAD = x^\circ$ and $\angle ADB = (3x+7)^\circ$. Since $BC \parallel AD$, $\angle BCA = \angle CAD = x^\circ$. Without further information about the angles, we cannot determine $x$ unless we assume $\angle ADB = \angle CAD$ (which is not necessarily true). If we assume the angles given are adjacent parts of the rhombus symmetry, we lack sufficient constraints. Given the options, if we assume $\angle ADB = \angle CAD$ is not the path, but rather that the total angle $D$ relates to $A$, we still lack info. Re-evaluating: if $\angle CAD = \angle ADB$, then $x = 3x+7 \implies -2x = 7$, impossible. If the problem implies $\angle CAD = \angle ADB$ is not the intended relation, and given the options, this is likely a poorly defined problem or requires an assumption like $\angle A + \angle D = 180^\circ$. Given the options, none are derived from standard properties without more info.