rhombus angle bisector property

In a rhombus, the diagonal bisects the vertex angle. Therefore, the two angles are equal: $2x + 3 = 3x + 2$. Solving for $x$: $3 - 2 = 3x - 2x$, so $x = 1$. Wait, checking the image again, the angles are adjacent to the diagonal $AC$ at vertex $A$. Since $AC$ bisects $\angle DAB$, $2x+3 = 3x+2$ gives $x=1$. However, if the angles are $\angle DAC$ and $\angle CAB$, then $2x+3 = 3x+2$ is correct. If the total angle is meant to be related to $90^\circ$, it is not specified. Given the options, let's re-evaluate: if $2x+3 + 3x+2 = 90$ (diagonals are perpendicular), $5x = 85$, $x = 17$.