distance formula and pythagorean theorem
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
The distance formula $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ simplifies to $d = \sqrt{x^2 + y^2}$ when one point is the origin $(0,0)$, which is identical to the Pythagorean theorem $a^2 + b^2 = c^2$.