congruence of triangles in a parallelogram
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
In a parallelogram, opposite sides are equal ($AB=CD$, $BC=AD$) and the diagonal $AC$ is common to both triangles. By the Side-Side-Side (SSS) congruence postulate, $\triangle ABC \cong \triangle CDA$.