circle chord bisected by perpendicular radius
Check the final answer first, then review the worked steps.
Problem
circle chord bisected by perpendicular radius
Step-by-step solution
A radius perpendicular to a chord bisects the chord. Since $AB = 8.5$ and $B$ is the midpoint of the chord $AC$, the total length is $2 \times 8.5 = 17$.
Answer
17