Calculate the distance between two points in 3D space.

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Problem

Calculate the distance between two points in 3D space.

Step-by-step solution

Using the distance formula in 3D, $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}$. For points K(-2, -4, -4) and L(4, 2, 0), $d = \sqrt{(4 - (-2))^2 + (2 - (-4))^2 + (0 - (-4))^2} = \sqrt{6^2 + 6^2 + 4^2} = \sqrt{36 + 36 + 16} = \sqrt{88}$.

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Answer

$6\sqrt{22}$