angle of intersecting secants

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Problem

angle of intersecting secants

Step-by-step solution

The angle formed by two secants intersecting outside a circle is half the difference of the intercepted arcs. Let $m\angle V = \frac{1}{2}(m\text{arc } TU - m\text{arc } RS) = \frac{1}{2}(120^\circ - 12^\circ) = \frac{108^\circ}{2} = 54^\circ$.

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Answer

54^\circ