angle of intersecting secants
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
The angle formed by two secants intersecting outside a circle is half the difference of the intercepted arcs. Let $m\angle V = \frac{1}{2}(m\text{arc } TU - m\text{arc } RS) = \frac{1}{2}(120^\circ - 12^\circ) = \frac{108^\circ}{2} = 54^\circ$.