table of values for functions f(x) = |x + 4| and g(x) = x^2 - 1, where f(x) = g(x)...

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Problem

table of values for functions f(x) = |x + 4| and g(x) = x^2 - 1, where f(x) = g(x) has a solution

Step-by-step solution

We need to find where $f(x) = g(x)$. From the table, at $x=-2$, $f(-2)=2$ and $g(-2)=3$. At $x=-1$, $f(-1)=3$ and $g(-1)=0$. Since $f(-2) < g(-2)$ and $f(-1) > g(-1)$, there is a solution between $x=-2$ and $x=-1$.

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Answer

between $x = -2$ and $x = -1$