Write a quadratic equation that can be solved to find the x-intercepts of the parab...
Check the final answer first, then review the worked steps.
Check the final answer first, then review the worked steps.
The vertex form of a parabola is $y = a(x-h)^2 + k$. Using the vertex $(-2, 4)$ and the point $(-4, -4)$, we find $a = -1$. The equation is $y = -(x+2)^2 + 4$. To find the x-intercepts, we set $y=0$, which gives $-(x+2)^2 + 4 = 0$. This simplifies to $x^2+4x = 0$.