graph reflection of quadratic function

1. Understand the transformation: The problem asks for the graph of $y = -f(x)$, where $f(x) = (x + 3)^2$. Multiplying a function by $-1$ results in a reflection of the original graph across the $x$-axis. This means every point $(x, y)$ on the graph of $f(x)$ will be mapped to the point $(x, -y)$ on the graph of $-f(x)$.

1. Analyze the original function: The original function $f(x) = (x + 3)^2$ is an upward-opening parabola with its vertex at $(-3, 0)$. It passes through points like $(-2, 1)$, $(-1, 4)$, and $(0, 9)$ (though $(0, 9)$ is off the provided grid).

1. Apply the transformation: Reflecting $f(x) = (x + 3)^2$ across the $x$-axis gives $y = -(x + 3)^2$. This new parabola will open downward and have the same vertex at $(-3, 0)$.

4. Evaluate the options:
- Option 1 is an upward-opening parabola with vertex at $(2, 0)$.
- Option 2 is a downward-opening parabola with vertex at $(-3, 0)$.
- Option 3 is a downward-opening parabola with vertex at $(2, 0)$.

1. Conclusion: Since the reflected graph must be a downward-opening parabola with its vertex at $(-3, 0)$, it matches the curve labeled 'Option 2'.